2b^2+20b-48=0

Solution for 2b^2+20b-48=0 equation:

Simplifying
2b2 + 20b + -48 = 0

Reorder the terms:
-48 + 20b + 2b2 = 0

Solving
-48 + 20b + 2b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-24 + 10b + b2) = 0

Factor a trinomial.
2((-12 + -1b)(2 + -1b)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-12 + -1b)' equal to zero and attempt to solve:

Simplifying
-12 + -1b = 0

Solving
-12 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1b = 0 + 12
-1b = 0 + 12

Combine like terms: 0 + 12 = 12
-1b = 12

Divide each side by '-1'.
b = -12

Simplifying
b = -12
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-12, 2}